4.9x^2-14x+10=0

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Solution for 4.9x^2-14x+10=0 equation: 



4.9x^2-14x+10=0

a = 4.9; b = -14; c = +10;
Δ = b2-4ac
Δ = -142-4·4.9·10
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{14}{9.8}=1+3.5/8.1666666666667$

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